Base | Representation |
---|---|
bin | 10010101000001010… |
… | …101011100101000011 |
3 | 1220121220212100010221 |
4 | 102220022223211003 |
5 | 311430304211121 |
6 | 13104412003511 |
7 | 1305435514114 |
oct | 225012534503 |
9 | 56556770127 |
10 | 20001241411 |
11 | 85341a7788 |
12 | 3a62460597 |
13 | 1b69a209b8 |
14 | d7a52a20b |
15 | 7c0e13b41 |
hex | 4a82ab943 |
20001241411 has 2 divisors, whose sum is σ = 20001241412. Its totient is φ = 20001241410.
The previous prime is 20001241399. The next prime is 20001241417. The reversal of 20001241411 is 11414210002.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20001241411 - 221 = 19999144259 is a prime.
It is a super-2 number, since 2×200012414112 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20001241417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10000620705 + 10000620706.
It is an arithmetic number, because the mean of its divisors is an integer number (10000620706).
Almost surely, 220001241411 is an apocalyptic number.
20001241411 is a deficient number, since it is larger than the sum of its proper divisors (1).
20001241411 is an equidigital number, since it uses as much as digits as its factorization.
20001241411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64, while the sum is 16.
Adding to 20001241411 its reverse (11414210002), we get a palindrome (31415451413).
The spelling of 20001241411 in words is "twenty billion, one million, two hundred forty-one thousand, four hundred eleven".
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