Base | Representation |
---|---|
bin | 1011101001000110101… |
… | …1001001010001011111 |
3 | 201010021012210212011120 |
4 | 2322101223021101133 |
5 | 11234111200031421 |
6 | 231515014022023 |
7 | 20310332134212 |
oct | 2722153112137 |
9 | 633235725146 |
10 | 200012502111 |
11 | 77908930224 |
12 | 3291b947913 |
13 | 15b26aa8886 |
14 | 9975a17779 |
15 | 53095e38c6 |
hex | 2e91ac945f |
200012502111 has 4 divisors (see below), whose sum is σ = 266683336152. Its totient is φ = 133341668072.
The previous prime is 200012502101. The next prime is 200012502119. The reversal of 200012502111 is 111205210002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 200012502111 - 211 = 200012500063 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200012502119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33335417016 + ... + 33335417021.
It is an arithmetic number, because the mean of its divisors is an integer number (66670834038).
Almost surely, 2200012502111 is an apocalyptic number.
200012502111 is a deficient number, since it is larger than the sum of its proper divisors (66670834041).
200012502111 is an equidigital number, since it uses as much as digits as its factorization.
200012502111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66670834040.
The product of its (nonzero) digits is 40, while the sum is 15.
Adding to 200012502111 its reverse (111205210002), we get a palindrome (311217712113).
The spelling of 200012502111 in words is "two hundred billion, twelve million, five hundred two thousand, one hundred eleven".
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