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2000131310311 = 9919512016361
BaseRepresentation
bin11101000110110001000…
…111011100001011100111
321002012200120221002211221
4131012301013130023213
5230232232103412221
64130503031241211
7264335055423661
oct35066107341347
97065616832757
102000131310311
11701283a88202
1228377bb19207
131167c481b394
146cb420b1531
15370647b9541
hex1d1b11dc2e7

2000131310311 has 4 divisors (see below), whose sum is σ = 2000134318624. Its totient is φ = 2000128302000.

The previous prime is 2000131310291. The next prime is 2000131310329. The reversal of 2000131310311 is 1130131310002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2000131310311 - 25 = 2000131310279 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2000131310341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16230 + ... + 2000131.

It is an arithmetic number, because the mean of its divisors is an integer number (500033579656).

Almost surely, 22000131310311 is an apocalyptic number.

2000131310311 is a deficient number, since it is larger than the sum of its proper divisors (3008313).

2000131310311 is an equidigital number, since it uses as much as digits as its factorization.

2000131310311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3008312.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 2000131310311 its reverse (1130131310002), we get a palindrome (3130262620313).

The spelling of 2000131310311 in words is "two trillion, one hundred thirty-one million, three hundred ten thousand, three hundred eleven".

Divisors: 1 991951 2016361 2000131310311