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200013241333 = 316452040043
BaseRepresentation
bin1011101001000110110…
…1111101101111110101
3201010021021012102012011
42322101231331233311
511234111342210313
6231515041524221
720310341333323
oct2722155755765
9633237172164
10200013241333
1177909295654
1232920043671
1315b26ca7199
149975b6ad13
1553096dc93d
hex2e91b7dbf5

200013241333 has 4 divisors (see below), whose sum is σ = 206465281408. Its totient is φ = 193561201260.

The previous prime is 200013241279. The next prime is 200013241343. The reversal of 200013241333 is 333142310002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200013241333 - 217 = 200013110261 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200013241343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3226019991 + ... + 3226020052.

It is an arithmetic number, because the mean of its divisors is an integer number (51616320352).

Almost surely, 2200013241333 is an apocalyptic number.

It is an amenable number.

200013241333 is a deficient number, since it is larger than the sum of its proper divisors (6452040075).

200013241333 is an equidigital number, since it uses as much as digits as its factorization.

200013241333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6452040074.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 200013241333 its reverse (333142310002), we get a palindrome (533155551335).

The spelling of 200013241333 in words is "two hundred billion, thirteen million, two hundred forty-one thousand, three hundred thirty-three".

Divisors: 1 31 6452040043 200013241333