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20001330113 = 103194187671
BaseRepresentation
bin10010101000001011…
…000001001111000001
31220121221000211211012
4102220023001033001
5311430320030423
613104413530305
71305436333532
oct225013011701
956557024735
1020001330113
118534258396
123a624a3995
131b69a5219b
14d7a550689
157c0e30078
hex4a82c13c1

20001330113 has 4 divisors (see below), whose sum is σ = 20195517888. Its totient is φ = 19807142340.

The previous prime is 20001330109. The next prime is 20001330157. The reversal of 20001330113 is 31103310002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20001330113 - 22 = 20001330109 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (20001330163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97093733 + ... + 97093938.

It is an arithmetic number, because the mean of its divisors is an integer number (5048879472).

Almost surely, 220001330113 is an apocalyptic number.

It is an amenable number.

20001330113 is a deficient number, since it is larger than the sum of its proper divisors (194187775).

20001330113 is a wasteful number, since it uses less digits than its factorization.

20001330113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 194187774.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 20001330113 its reverse (31103310002), we get a palindrome (51104640115).

The spelling of 20001330113 in words is "twenty billion, one million, three hundred thirty thousand, one hundred thirteen".

Divisors: 1 103 194187671 20001330113