Base | Representation |
---|---|
bin | 101101011110100101101111… |
… | …100001101010011110000111 |
3 | 222020012011121201021110020101 |
4 | 231132211233201222132013 |
5 | 202204013041443244421 |
6 | 1545221131215144531 |
7 | 60062356260563425 |
oct | 5536455741523607 |
9 | 866164551243211 |
10 | 200014203103111 |
11 | 588046023239a1 |
12 | 1a524113b15147 |
13 | 877b3489a05c7 |
14 | 3756a4c08a115 |
15 | 181cc65e41191 |
hex | b5e96f86a787 |
200014203103111 has 4 divisors (see below), whose sum is σ = 200015670662752. Its totient is φ = 200012735543472.
The previous prime is 200014203103087. The next prime is 200014203103157. The reversal of 200014203103111 is 111301302410002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 200014203103111 - 221 = 200014201005959 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200014203107111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 733575366 + ... + 733847971.
It is an arithmetic number, because the mean of its divisors is an integer number (50003917665688).
Almost surely, 2200014203103111 is an apocalyptic number.
200014203103111 is a deficient number, since it is larger than the sum of its proper divisors (1467559641).
200014203103111 is a wasteful number, since it uses less digits than its factorization.
200014203103111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1467559640.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 200014203103111 its reverse (111301302410002), we get a palindrome (311315505513113).
The spelling of 200014203103111 in words is "two hundred trillion, fourteen billion, two hundred three million, one hundred three thousand, one hundred eleven".
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