Base | Representation |
---|---|
bin | 1011101001000111000… |
… | …1101010011111101011 |
3 | 201010021100000200101122 |
4 | 2322101301222133223 |
5 | 11234112114223201 |
6 | 231515114405455 |
7 | 20310352512434 |
oct | 2722161523753 |
9 | 633240020348 |
10 | 200014211051 |
11 | 77909898176 |
12 | 3292043088b |
13 | 15b27256695 |
14 | 9975d4048b |
15 | 530982ee1b |
hex | 2e91c6a7eb |
200014211051 has 4 divisors (see below), whose sum is σ = 200042274600. Its totient is φ = 199986147504.
The previous prime is 200014211021. The next prime is 200014211053. The reversal of 200014211051 is 150112410002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 200014211051 - 222 = 200010016747 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (200014211053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14021081 + ... + 14035338.
It is an arithmetic number, because the mean of its divisors is an integer number (50010568650).
Almost surely, 2200014211051 is an apocalyptic number.
200014211051 is a deficient number, since it is larger than the sum of its proper divisors (28063549).
200014211051 is an equidigital number, since it uses as much as digits as its factorization.
200014211051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28063548.
The product of its (nonzero) digits is 80, while the sum is 17.
Adding to 200014211051 its reverse (150112410002), we get a palindrome (350126621053).
The spelling of 200014211051 in words is "two hundred billion, fourteen million, two hundred eleven thousand, fifty-one".
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