20002011212013 has 4 divisors (see below), whose sum is σ = 26669348282688. Its totient is φ = 13334674141340.

The previous prime is 20002011212003. The next prime is 20002011212017. The reversal of 20002011212013 is 31021211020002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20002011212013 - 2⁸ = 20002011211757 is a prime.

It is a super-2 number, since 2×20002011212013² (a number of 27 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 20002011211983 and 20002011212001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20002011212017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3333668535333 + ... + 3333668535338.

It is an arithmetic number, because the mean of its divisors is an integer number (6667337070672).

Almost surely, 2^{20002011212013} is an apocalyptic number.

It is an amenable number.

20002011212013 is a deficient number, since it is larger than the sum of its proper divisors (6667337070675).

20002011212013 is an equidigital number, since it uses as much as digits as its factorization.

20002011212013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6667337070674.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 20002011212013 its reverse (31021211020002), we get a palindrome (51023222232015).

The spelling of 20002011212013 in words is "twenty trillion, two billion, eleven million, two hundred twelve thousand, thirteen".