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200020112197 = 431464083787
BaseRepresentation
bin1011101001001000100…
…0001011001101000101
3201010021202010111020121
42322102020023031011
511234120122042242
6231515445101541
720310453621103
oct2722210131505
9633252114217
10200020112197
1177912158854
12329223b78b1
1315b28541699
149976a38c73
15530a0e8667
hex2e9220b345

200020112197 has 4 divisors (see below), whose sum is σ = 200484196416. Its totient is φ = 199556027980.

The previous prime is 200020112177. The next prime is 200020112309. The reversal of 200020112197 is 791211020002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200020112197 - 215 = 200020079429 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200020112177) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 232041463 + ... + 232042324.

It is an arithmetic number, because the mean of its divisors is an integer number (50121049104).

Almost surely, 2200020112197 is an apocalyptic number.

It is an amenable number.

200020112197 is a deficient number, since it is larger than the sum of its proper divisors (464084219).

200020112197 is an equidigital number, since it uses as much as digits as its factorization.

200020112197 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 464084218.

The product of its (nonzero) digits is 504, while the sum is 25.

Adding to 200020112197 its reverse (791211020002), we get a palindrome (991231132199).

The spelling of 200020112197 in words is "two hundred billion, twenty million, one hundred twelve thousand, one hundred ninety-seven".

Divisors: 1 431 464083787 200020112197