Base | Representation |
---|---|
bin | 101101011110101101000110… |
… | …111000010100011111011011 |
3 | 222020012221000211120212212022 |
4 | 231132231012320110133123 |
5 | 202204130240421024011 |
6 | 1545224520031205055 |
7 | 60063056243543411 |
oct | 5536550670243733 |
9 | 866187024525768 |
10 | 200022111111131 |
11 | 588079a017a411 |
12 | 1a52576037678b |
13 | 877c009144baa |
14 | 375719c4492b1 |
15 | 181d07a3198db |
hex | b5eb46e147db |
200022111111131 has 2 divisors, whose sum is σ = 200022111111132. Its totient is φ = 200022111111130.
The previous prime is 200022111111023. The next prime is 200022111111181. The reversal of 200022111111131 is 131111111220002.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-200022111111131 is a prime.
It is a super-2 number, since 2×2000221111111312 (a number of 29 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (200022111111181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100011055555565 + 100011055555566.
It is an arithmetic number, because the mean of its divisors is an integer number (100011055555566).
Almost surely, 2200022111111131 is an apocalyptic number.
200022111111131 is a deficient number, since it is larger than the sum of its proper divisors (1).
200022111111131 is an equidigital number, since it uses as much as digits as its factorization.
200022111111131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 17.
Adding to 200022111111131 its reverse (131111111220002), we get a palindrome (331133222331133).
The spelling of 200022111111131 in words is "two hundred trillion, twenty-two billion, one hundred eleven million, one hundred eleven thousand, one hundred thirty-one".
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