Base | Representation |
---|---|
bin | 1001000110001010100010… |
… | …00001010101011111000001 |
3 | 2121211021021222220010012221 |
4 | 10203011101001111133001 |
5 | 10110212142113031423 |
6 | 110313132250051041 |
7 | 4133112350432443 |
oct | 443052101253701 |
9 | 77737258803187 |
10 | 20003022002113 |
11 | 6412263495a47 |
12 | 22b0877719a81 |
13 | b2137a3cca77 |
14 | 4d2219750493 |
15 | 24a4d0323e5d |
hex | 1231510557c1 |
20003022002113 has 2 divisors, whose sum is σ = 20003022002114. Its totient is φ = 20003022002112.
The previous prime is 20003022002111. The next prime is 20003022002141. The reversal of 20003022002113 is 31120022030002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19568440446129 + 434581555984 = 4423623^2 + 659228^2 .
It is a cyclic number.
It is not a de Polignac number, because 20003022002113 - 21 = 20003022002111 is a prime.
Together with 20003022002111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (20003022002111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10001511001056 + 10001511001057.
It is an arithmetic number, because the mean of its divisors is an integer number (10001511001057).
Almost surely, 220003022002113 is an apocalyptic number.
It is an amenable number.
20003022002113 is a deficient number, since it is larger than the sum of its proper divisors (1).
20003022002113 is an equidigital number, since it uses as much as digits as its factorization.
20003022002113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 16.
Adding to 20003022002113 its reverse (31120022030002), we get a palindrome (51123044032115).
The spelling of 20003022002113 in words is "twenty trillion, three billion, twenty-two million, two thousand, one hundred thirteen".
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