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20003221032013 = 43465191186791
BaseRepresentation
bin1001000110001010111001…
…11000100100110001001101
32121211021210212101212220201
410203011130320210301031
510110213044041011023
6110313204120013501
74133120315236522
oct443053470446115
977737725355821
1020003221032013
11641235587606a
1222b0912301291
13b213ac70763b
144d2237d5d149
1524a4e2a3abad
hex12315ce24c4d

20003221032013 has 4 divisors (see below), whose sum is σ = 20468412218848. Its totient is φ = 19538029845180.

The previous prime is 20003221031977. The next prime is 20003221032017. The reversal of 20003221032013 is 31023012230002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20003221032013 - 29 = 20003221031501 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20003221032017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 232595593353 + ... + 232595593438.

It is an arithmetic number, because the mean of its divisors is an integer number (5117103054712).

Almost surely, 220003221032013 is an apocalyptic number.

It is an amenable number.

20003221032013 is a deficient number, since it is larger than the sum of its proper divisors (465191186835).

20003221032013 is an equidigital number, since it uses as much as digits as its factorization.

20003221032013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 465191186834.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 20003221032013 its reverse (31023012230002), we get a palindrome (51026233262015).

The spelling of 20003221032013 in words is "twenty trillion, three billion, two hundred twenty-one million, thirty-two thousand, thirteen".

Divisors: 1 43 465191186791 20003221032013