Base | Representation |
---|---|
bin | 111011100111011… |
… | …1101100110101011 |
3 | 12011102010102002012 |
4 | 1313032331212223 |
5 | 13044101123201 |
6 | 530255430135 |
7 | 100400133122 |
oct | 16716754653 |
9 | 5142112065 |
10 | 2000411051 |
11 | 9371a8481 |
12 | 479b2534b |
13 | 25b58c4a2 |
14 | 14d964ab9 |
15 | ba9445bb |
hex | 773bd9ab |
2000411051 has 2 divisors, whose sum is σ = 2000411052. Its totient is φ = 2000411050.
The previous prime is 2000411047. The next prime is 2000411053. The reversal of 2000411051 is 1501140002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2000411051 - 22 = 2000411047 is a prime.
It is a Sophie Germain prime.
Together with 2000411053, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2000411053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000205525 + 1000205526.
It is an arithmetic number, because the mean of its divisors is an integer number (1000205526).
Almost surely, 22000411051 is an apocalyptic number.
2000411051 is a deficient number, since it is larger than the sum of its proper divisors (1).
2000411051 is an equidigital number, since it uses as much as digits as its factorization.
2000411051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40, while the sum is 14.
The square root of 2000411051 is about 44725.9550037783. The cubic root of 2000411051 is about 1260.0073592835.
Adding to 2000411051 its reverse (1501140002), we get a palindrome (3501551053).
The spelling of 2000411051 in words is "two billion, four hundred eleven thousand, fifty-one".
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