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200041323311 = 240169832919
BaseRepresentation
bin1011101001001101100…
…1000101101100101111
3201010100020001010102102
42322103121011230233
511234141034321221
6231521523445315
720311132123064
oct2722331055457
9633306033372
10200041323311
1177923125aa5
123292952683b
1315b2ca5a13b
14997979ac6b
15530bdd830b
hex2e93645b2f

200041323311 has 4 divisors (see below), whose sum is σ = 200042396400. Its totient is φ = 200040250224.

The previous prime is 200041323299. The next prime is 200041323337. The reversal of 200041323311 is 113323140002.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 200041323311 - 222 = 200037129007 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200041923311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 176291 + ... + 656628.

It is an arithmetic number, because the mean of its divisors is an integer number (50010599100).

Almost surely, 2200041323311 is an apocalyptic number.

200041323311 is a deficient number, since it is larger than the sum of its proper divisors (1073089).

200041323311 is an equidigital number, since it uses as much as digits as its factorization.

200041323311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1073088.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 200041323311 its reverse (113323140002), we get a palindrome (313364463313).

The spelling of 200041323311 in words is "two hundred billion, forty-one million, three hundred twenty-three thousand, three hundred eleven".

Divisors: 1 240169 832919 200041323311