Base | Representation |
---|---|
bin | 11101000111000001111… |
… | …110100101000110010011 |
3 | 21002020102022020101211122 |
4 | 131013001332211012103 |
5 | 230233322013401321 |
6 | 4130551054432455 |
7 | 264345062101610 |
oct | 35070176450623 |
9 | 7066368211748 |
10 | 2000414200211 |
11 | 701409735609 |
12 | 28383a80272b |
13 | 11683b30825b |
14 | 6cb6b8ad507 |
15 | 3707e5488ab |
hex | 1d1c1fa5193 |
2000414200211 has 4 divisors (see below), whose sum is σ = 2286187657392. Its totient is φ = 1714640743032.
The previous prime is 2000414200207. The next prime is 2000414200217. The reversal of 2000414200211 is 1120024140002.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 2000414200211 - 22 = 2000414200207 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 2000414200211.
It is not an unprimeable number, because it can be changed into a prime (2000414200217) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142886728580 + ... + 142886728593.
It is an arithmetic number, because the mean of its divisors is an integer number (571546914348).
Almost surely, 22000414200211 is an apocalyptic number.
2000414200211 is a deficient number, since it is larger than the sum of its proper divisors (285773457181).
2000414200211 is an equidigital number, since it uses as much as digits as its factorization.
2000414200211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 285773457180.
The product of its (nonzero) digits is 128, while the sum is 17.
Adding to 2000414200211 its reverse (1120024140002), we get a palindrome (3120438340213).
The spelling of 2000414200211 in words is "two trillion, four hundred fourteen million, two hundred thousand, two hundred eleven".
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