Base | Representation |
---|---|
bin | 10010101000010101… |
… | …101111110000111111 |
3 | 1220122010022201012110 |
4 | 102220111233300333 |
5 | 311432030022033 |
6 | 13104554105103 |
7 | 1305502255056 |
oct | 225025576077 |
9 | 56563281173 |
10 | 20004142143 |
11 | 85358a9087 |
12 | 3a6341b193 |
13 | 1b6a4c80cb |
14 | d7aa8339d |
15 | 7c12d8363 |
hex | 4a856fc3f |
20004142143 has 4 divisors (see below), whose sum is σ = 26672189528. Its totient is φ = 13336094760.
The previous prime is 20004142141. The next prime is 20004142157. The reversal of 20004142143 is 34124140002.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 20004142143 - 21 = 20004142141 is a prime.
It is a super-3 number, since 3×200041421433 (a number of 32 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20004142141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3334023688 + ... + 3334023693.
It is an arithmetic number, because the mean of its divisors is an integer number (6668047382).
Almost surely, 220004142143 is an apocalyptic number.
20004142143 is a deficient number, since it is larger than the sum of its proper divisors (6668047385).
20004142143 is an equidigital number, since it uses as much as digits as its factorization.
20004142143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6668047384.
The product of its (nonzero) digits is 768, while the sum is 21.
Adding to 20004142143 its reverse (34124140002), we get a palindrome (54128282145).
The spelling of 20004142143 in words is "twenty billion, four million, one hundred forty-two thousand, one hundred forty-three".
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