Base | Representation |
---|---|
bin | 111011100111100… |
… | …0101001001111111 |
3 | 12011102011222111211 |
4 | 1313033011021333 |
5 | 13044103120413 |
6 | 530300225251 |
7 | 100400322241 |
oct | 16717051177 |
9 | 5142158454 |
10 | 2000441983 |
11 | 937219741 |
12 | 479b3b227 |
13 | 25b5a05a7 |
14 | 14d972091 |
15 | ba94d83d |
hex | 773c527f |
2000441983 has 2 divisors, whose sum is σ = 2000441984. Its totient is φ = 2000441982.
The previous prime is 2000441977. The next prime is 2000441987. The reversal of 2000441983 is 3891440002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2000441983 - 229 = 1463571071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2000441987) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000220991 + 1000220992.
It is an arithmetic number, because the mean of its divisors is an integer number (1000220992).
Almost surely, 22000441983 is an apocalyptic number.
2000441983 is a deficient number, since it is larger than the sum of its proper divisors (1).
2000441983 is an equidigital number, since it uses as much as digits as its factorization.
2000441983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 31.
The square root of 2000441983 is about 44726.3007971820. The cubic root of 2000441983 is about 1260.0138536732.
Adding to 2000441983 its reverse (3891440002), we get a palindrome (5891881985).
The spelling of 2000441983 in words is "two billion, four hundred forty-one thousand, nine hundred eighty-three".
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