Base | Representation |
---|---|
bin | 1001000110010111100010… |
… | …00000100011101100000011 |
3 | 2121211221022101100001010201 |
4 | 10203023301000203230003 |
5 | 10110320440241320003 |
6 | 110320245000510031 |
7 | 4133450324110066 |
oct | 443136100435403 |
9 | 77757271301121 |
10 | 20010001120003 |
11 | 6415214a77574 |
12 | 22b20a4a7b317 |
13 | b21c202a3c1b |
14 | 4d26bc5d28dd |
15 | 24a78cdb5b1d |
hex | 1232f1023b03 |
20010001120003 has 2 divisors, whose sum is σ = 20010001120004. Its totient is φ = 20010001120002.
The previous prime is 20010001119961. The next prime is 20010001120013. The reversal of 20010001120003 is 30002110001002.
It is an a-pointer prime, because the next prime (20010001120013) can be obtained adding 20010001120003 to its sum of digits (10).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20010001120003 - 225 = 20009967565571 is a prime.
It is not a weakly prime, because it can be changed into another prime (20010001120013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005000560001 + 10005000560002.
It is an arithmetic number, because the mean of its divisors is an integer number (10005000560002).
Almost surely, 220010001120003 is an apocalyptic number.
20010001120003 is a deficient number, since it is larger than the sum of its proper divisors (1).
20010001120003 is an equidigital number, since it uses as much as digits as its factorization.
20010001120003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 10.
Adding to 20010001120003 its reverse (30002110001002), we get a palindrome (50012111121005).
The spelling of 20010001120003 in words is "twenty trillion, ten billion, one million, one hundred twenty thousand, three".
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