Base | Representation |
---|---|
bin | 1001000110010111101110… |
… | …00001011011010100000111 |
3 | 2121211221120102011211202121 |
4 | 10203023313001123110013 |
5 | 10110321142103324033 |
6 | 110320303003150411 |
7 | 4133452660503256 |
oct | 443136701332407 |
9 | 77757512154677 |
10 | 20010102011143 |
11 | 6415266a17582 |
12 | 22b2112815407 |
13 | b21c3816a21a |
14 | 4d26cbb7679d |
15 | 24a796b9462d |
hex | 1232f705b507 |
20010102011143 has 2 divisors, whose sum is σ = 20010102011144. Its totient is φ = 20010102011142.
The previous prime is 20010102011101. The next prime is 20010102011171. The reversal of 20010102011143 is 34111020101002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20010102011143 - 233 = 20001512076551 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20010102011443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005051005571 + 10005051005572.
It is an arithmetic number, because the mean of its divisors is an integer number (10005051005572).
Almost surely, 220010102011143 is an apocalyptic number.
20010102011143 is a deficient number, since it is larger than the sum of its proper divisors (1).
20010102011143 is an equidigital number, since it uses as much as digits as its factorization.
20010102011143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 20010102011143 its reverse (34111020101002), we get a palindrome (54121122112145).
The spelling of 20010102011143 in words is "twenty trillion, ten billion, one hundred two million, eleven thousand, one hundred forty-three".
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