Base | Representation |
---|---|
bin | 1001000110010111111001… |
… | …11011100000010011011011 |
3 | 2121211221211022200012022111 |
4 | 10203023330323200103123 |
5 | 10110321342441401021 |
6 | 110320320503333151 |
7 | 4133455303103242 |
oct | 443137473402333 |
9 | 77757738605274 |
10 | 20010201122011 |
11 | 6415307960a91 |
12 | 22b213ba511b7 |
13 | b21c5285c0c9 |
14 | 4d26dadb5959 |
15 | 24a7a07208e1 |
hex | 1232fcee04db |
20010201122011 has 2 divisors, whose sum is σ = 20010201122012. Its totient is φ = 20010201122010.
The previous prime is 20010201121969. The next prime is 20010201122057. The reversal of 20010201122011 is 11022110201002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20010201122011 - 215 = 20010201089243 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20010201121982 and 20010201122000.
It is not a weakly prime, because it can be changed into another prime (20010201122111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005100561005 + 10005100561006.
It is an arithmetic number, because the mean of its divisors is an integer number (10005100561006).
Almost surely, 220010201122011 is an apocalyptic number.
20010201122011 is a deficient number, since it is larger than the sum of its proper divisors (1).
20010201122011 is an equidigital number, since it uses as much as digits as its factorization.
20010201122011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 20010201122011 its reverse (11022110201002), we get a palindrome (31032311323013).
The spelling of 20010201122011 in words is "twenty trillion, ten billion, two hundred one million, one hundred twenty-two thousand, eleven".
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