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20010202017 = 3131211942337
BaseRepresentation
bin10010101000101100…
…110111001110100001
31220122112201120210020
4102220230313032201
5311440102431032
613105332024053
71305604624251
oct225054671641
956575646706
1020010202017
118539267a43
123a65462029
131b6b83a430
14d7b7bd961
157c1ad3b2c
hex4a8b373a1

20010202017 has 16 divisors (see below), whose sum is σ = 28735647360. Its totient is φ = 12312663552.

The previous prime is 20010201989. The next prime is 20010202033. The reversal of 20010202017 is 71020201002.

It is not a de Polignac number, because 20010202017 - 27 = 20010201889 is a prime.

It is a super-2 number, since 2×200102020172 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20010201987 and 20010202005.

It is not an unprimeable number, because it can be changed into a prime (20010202067) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 451473 + ... + 493809.

It is an arithmetic number, because the mean of its divisors is an integer number (1795977960).

Almost surely, 220010202017 is an apocalyptic number.

It is an amenable number.

20010202017 is a deficient number, since it is larger than the sum of its proper divisors (8725445343).

20010202017 is a wasteful number, since it uses less digits than its factorization.

20010202017 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 54472.

The product of its (nonzero) digits is 56, while the sum is 15.

Adding to 20010202017 its reverse (71020201002), we get a palindrome (91030403019).

The spelling of 20010202017 in words is "twenty billion, ten million, two hundred two thousand, seventeen".

Divisors: 1 3 13 39 12119 36357 42337 127011 157547 472641 550381 1651143 513082103 1539246309 6670067339 20010202017