Base | Representation |
---|---|
bin | 101101011111110111100110… |
… | …101010000111101010001111 |
3 | 222020111120111110222002212012 |
4 | 231133313212222013222033 |
5 | 202211433100343420242 |
6 | 1545325345231331435 |
7 | 60101620414645652 |
oct | 5537674652075217 |
9 | 866446443862765 |
10 | 200102101154447 |
11 | 588389084a5928 |
12 | 1a539164980b7b |
13 | 87867161a1a7b |
14 | 375adc9b51899 |
15 | 18201ac9bd282 |
hex | b5fde6a87a8f |
200102101154447 has 2 divisors, whose sum is σ = 200102101154448. Its totient is φ = 200102101154446.
The previous prime is 200102101154437. The next prime is 200102101154467. The reversal of 200102101154447 is 744451101201002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200102101154447 - 238 = 199827223247503 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200102101154437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100051050577223 + 100051050577224.
It is an arithmetic number, because the mean of its divisors is an integer number (100051050577224).
Almost surely, 2200102101154447 is an apocalyptic number.
200102101154447 is a deficient number, since it is larger than the sum of its proper divisors (1).
200102101154447 is an equidigital number, since it uses as much as digits as its factorization.
200102101154447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8960, while the sum is 32.
Adding to 200102101154447 its reverse (744451101201002), we get a palindrome (944553202355449).
The spelling of 200102101154447 in words is "two hundred trillion, one hundred two billion, one hundred one million, one hundred fifty-four thousand, four hundred forty-seven".
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