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20010312703 is a prime number
BaseRepresentation
bin10010101000101101…
…010010001111111111
31220122112221012121201
4102220231102033333
5311440120001303
613105334240331
71305605565043
oct225055221777
956575835551
1020010312703
118539333117
123a654b60a7
131b6b878924
14d7b80c023
157c1b0681d
hex4a8b523ff

20010312703 has 2 divisors, whose sum is σ = 20010312704. Its totient is φ = 20010312702.

The previous prime is 20010312671. The next prime is 20010312709. The reversal of 20010312703 is 30721301002.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 20010312703 - 25 = 20010312671 is a prime.

It is a super-2 number, since 2×200103127032 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20010312709) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005156351 + 10005156352.

It is an arithmetic number, because the mean of its divisors is an integer number (10005156352).

Almost surely, 220010312703 is an apocalyptic number.

20010312703 is a deficient number, since it is larger than the sum of its proper divisors (1).

20010312703 is an equidigital number, since it uses as much as digits as its factorization.

20010312703 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 19.

Adding to 20010312703 its reverse (30721301002), we get a palindrome (50731613705).

The spelling of 20010312703 in words is "twenty billion, ten million, three hundred twelve thousand, seven hundred three".