Base | Representation |
---|---|
bin | 11101000111100111011… |
… | …010000010101010000111 |
3 | 21002022001001211212110122 |
4 | 131013213122002222013 |
5 | 230241113242444132 |
6 | 4131133250012155 |
7 | 264366455454155 |
oct | 35074732025207 |
9 | 7068031755418 |
10 | 2001042156167 |
11 | 70170114817a |
12 | 283994b7705b |
13 | 11690b441622 |
14 | 6cbcb0523d5 |
15 | 370b9739912 |
hex | 1d1e7682a87 |
2001042156167 has 2 divisors, whose sum is σ = 2001042156168. Its totient is φ = 2001042156166.
The previous prime is 2001042156149. The next prime is 2001042156247. The reversal of 2001042156167 is 7616512401002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2001042156167 - 28 = 2001042155911 is a prime.
It is a super-2 number, since 2×20010421561672 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2001042156767) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000521078083 + 1000521078084.
It is an arithmetic number, because the mean of its divisors is an integer number (1000521078084).
Almost surely, 22001042156167 is an apocalyptic number.
2001042156167 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001042156167 is an equidigital number, since it uses as much as digits as its factorization.
2001042156167 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 35.
Adding to 2001042156167 its reverse (7616512401002), we get a palindrome (9617554557169).
The spelling of 2001042156167 in words is "two trillion, one billion, forty-two million, one hundred fifty-six thousand, one hundred sixty-seven".
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