Base | Representation |
---|---|
bin | 11101000111101010110… |
… | …111000101001001001011 |
3 | 21002022012002212201200212 |
4 | 131013222313011021023 |
5 | 230241223111201141 |
6 | 4131143115551335 |
7 | 264401061126134 |
oct | 35075267051113 |
9 | 7068162781625 |
10 | 2001100100171 |
11 | 701730924387 |
12 | 2839b045b54b |
13 | 11691a44b813 |
14 | 6cbd4a16c8b |
15 | 370be8832eb |
hex | 1d1eadc524b |
2001100100171 has 2 divisors, whose sum is σ = 2001100100172. Its totient is φ = 2001100100170.
The previous prime is 2001100100063. The next prime is 2001100100173. The reversal of 2001100100171 is 1710010011002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2001100100171 - 222 = 2001095905867 is a prime.
It is a super-2 number, since 2×20011001001712 (a number of 25 digits) contains 22 as substring.
Together with 2001100100173, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2001100100173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000550050085 + 1000550050086.
It is an arithmetic number, because the mean of its divisors is an integer number (1000550050086).
Almost surely, 22001100100171 is an apocalyptic number.
2001100100171 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001100100171 is an equidigital number, since it uses as much as digits as its factorization.
2001100100171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14, while the sum is 14.
Adding to 2001100100171 its reverse (1710010011002), we get a palindrome (3711110111173).
The spelling of 2001100100171 in words is "two trillion, one billion, one hundred million, one hundred thousand, one hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •