Base | Representation |
---|---|
bin | 101101011111111111000100… |
… | …000001110100111000110111 |
3 | 222020112100011122012202012001 |
4 | 231133333010001310320313 |
5 | 202212101001141213142 |
6 | 1545333152051040131 |
7 | 60102323034610336 |
oct | 5537770401647067 |
9 | 866470148182161 |
10 | 200110110101047 |
11 | 58841248323a63 |
12 | 1a53a81aba0047 |
13 | 87873c1528123 |
14 | 375b5496a7d1d |
15 | 18204cab845b7 |
hex | b5ffc4074e37 |
200110110101047 has 2 divisors, whose sum is σ = 200110110101048. Its totient is φ = 200110110101046.
The previous prime is 200110110100991. The next prime is 200110110101063. The reversal of 200110110101047 is 740101011011002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200110110101047 - 27 = 200110110100919 is a prime.
It is a super-3 number, since 3×2001101101010473 (a number of 44 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200110110101147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100055055050523 + 100055055050524.
It is an arithmetic number, because the mean of its divisors is an integer number (100055055050524).
Almost surely, 2200110110101047 is an apocalyptic number.
200110110101047 is a deficient number, since it is larger than the sum of its proper divisors (1).
200110110101047 is an equidigital number, since it uses as much as digits as its factorization.
200110110101047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 19.
Adding to 200110110101047 its reverse (740101011011002), we get a palindrome (940211121112049).
The spelling of 200110110101047 in words is "two hundred trillion, one hundred ten billion, one hundred ten million, one hundred one thousand, forty-seven".
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