Base | Representation |
---|---|
bin | 111011101000110… |
… | …1000100001000011 |
3 | 12011110102222101012 |
4 | 1313101220201003 |
5 | 13044241023412 |
6 | 530322431135 |
7 | 100406110112 |
oct | 16721504103 |
9 | 5143388335 |
10 | 2001111107 |
11 | 937636436 |
12 | 47a2024ab |
13 | 25b776018 |
14 | 14daa7c79 |
15 | baa31c22 |
hex | 77468843 |
2001111107 has 2 divisors, whose sum is σ = 2001111108. Its totient is φ = 2001111106.
The previous prime is 2001111061. The next prime is 2001111121. The reversal of 2001111107 is 7011111002.
It is an a-pointer prime, because the next prime (2001111121) can be obtained adding 2001111107 to its sum of digits (14).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2001111107 - 214 = 2001094723 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2001111091 and 2001111100.
It is not a weakly prime, because it can be changed into another prime (2001311107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000555553 + 1000555554.
It is an arithmetic number, because the mean of its divisors is an integer number (1000555554).
Almost surely, 22001111107 is an apocalyptic number.
2001111107 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001111107 is an equidigital number, since it uses as much as digits as its factorization.
2001111107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14, while the sum is 14.
The square root of 2001111107 is about 44733.7803790379. The cubic root of 2001111107 is about 1260.1543245510.
Adding to 2001111107 its reverse (7011111002), we get a palindrome (9012222109).
The spelling of 2001111107 in words is "two billion, one million, one hundred eleven thousand, one hundred seven".
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