200111330003 has 4 divisors (see below), whose sum is σ = 215504509248. Its totient is φ = 184718150760.

The previous prime is 200111329993. The next prime is 200111330009. The reversal of 200111330003 is 300033111002.

200111330003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 200111330003 - 2¹⁰ = 200111328979 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 200111330003.

It is not an unprimeable number, because it can be changed into a prime (200111330009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7696589603 + ... + 7696589628.

It is an arithmetic number, because the mean of its divisors is an integer number (53876127312).

Almost surely, 2^200111330003 is an apocalyptic number.

200111330003 is a deficient number, since it is larger than the sum of its proper divisors (15393179245).

200111330003 is a wasteful number, since it uses less digits than its factorization.

200111330003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15393179244.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 200111330003 its reverse (300033111002), we get a palindrome (500144441005).

The spelling of 200111330003 in words is "two hundred billion, one hundred eleven million, three hundred thirty thousand, three".