Base | Representation |
---|---|
bin | 1011101001011110011… |
… | …0101111011011111011 |
3 | 201010112011001102201002 |
4 | 2322113212233123323 |
5 | 11234312133323003 |
6 | 231532530515215 |
7 | 20312651012462 |
oct | 2722746573373 |
9 | 633464042632 |
10 | 200112011003 |
11 | 7795a016783 |
12 | 32949135b0b |
13 | 15b415a9988 |
14 | 9984d1b9d9 |
15 | 53131eca88 |
hex | 2e979af6fb |
200112011003 has 4 divisors (see below), whose sum is σ = 200241702768. Its totient is φ = 199982319240.
The previous prime is 200112010951. The next prime is 200112011051. The reversal of 200112011003 is 300110211002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 200112011003 - 224 = 200095233787 is a prime.
It is a super-3 number, since 3×2001120110033 (a number of 35 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (200112011063) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64843568 + ... + 64846653.
It is an arithmetic number, because the mean of its divisors is an integer number (50060425692).
Almost surely, 2200112011003 is an apocalyptic number.
200112011003 is a deficient number, since it is larger than the sum of its proper divisors (129691765).
200112011003 is a wasteful number, since it uses less digits than its factorization.
200112011003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 129691764.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 200112011003 its reverse (300110211002), we get a palindrome (500222222005).
The spelling of 200112011003 in words is "two hundred billion, one hundred twelve million, eleven thousand, three".
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