Base | Representation |
---|---|
bin | 11101000111101100000… |
… | …011110101010000110100 |
3 | 21002022020111201221012120 |
4 | 131013230003311100310 |
5 | 230241243234021322 |
6 | 4131145115115540 |
7 | 264401424135141 |
oct | 35075403652064 |
9 | 7068214657176 |
10 | 2001120220212 |
11 | 701741216913 |
12 | 2839b7142bb0 |
13 | 116921674779 |
14 | 6cbd75733c8 |
15 | 370c1509a5c |
hex | 1d1ec0f5434 |
2001120220212 has 48 divisors (see below), whose sum is σ = 4876756624320. Its totient is φ = 638011752192.
The previous prime is 2001120220189. The next prime is 2001120220213. The reversal of 2001120220212 is 2120220211002.
It is a junction number, because it is equal to n+sod(n) for n = 2001120220191 and 2001120220200.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2001120220213) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 38168953 + ... + 38221344.
It is an arithmetic number, because the mean of its divisors is an integer number (101599096340).
Almost surely, 22001120220212 is an apocalyptic number.
It is an amenable number.
2001120220212 is an abundant number, since it is smaller than the sum of its proper divisors (2875636404108).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2001120220212 is a wasteful number, since it uses less digits than its factorization.
2001120220212 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 76390400 (or 76390398 counting only the distinct ones).
The product of its (nonzero) digits is 64, while the sum is 15.
Adding to 2001120220212 its reverse (2120220211002), we get a palindrome (4121340431214).
The spelling of 2001120220212 in words is "two trillion, one billion, one hundred twenty million, two hundred twenty thousand, two hundred twelve".
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