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200112100117 is a prime number
BaseRepresentation
bin1011101001011110011…
…1000101001100010101
3201010112011012221221121
42322113213011030111
511234312144200432
6231532532443541
720312651533336
oct2722747051425
9633464187847
10200112100117
117795a077726
12329491795b1
1315b4160b3c7
149984d4228d
155313219197
hex2e979c5315

200112100117 has 2 divisors, whose sum is σ = 200112100118. Its totient is φ = 200112100116.

The previous prime is 200112100087. The next prime is 200112100127. The reversal of 200112100117 is 711001211002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 194398100836 + 5713999281 = 440906^2 + 75591^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200112100117 is a prime.

It is a super-2 number, since 2×2001121001172 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 200112100117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200112100127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100056050058 + 100056050059.

It is an arithmetic number, because the mean of its divisors is an integer number (100056050059).

Almost surely, 2200112100117 is an apocalyptic number.

It is an amenable number.

200112100117 is a deficient number, since it is larger than the sum of its proper divisors (1).

200112100117 is an equidigital number, since it uses as much as digits as its factorization.

200112100117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28, while the sum is 16.

Adding to 200112100117 its reverse (711001211002), we get a palindrome (911113311119).

The spelling of 200112100117 in words is "two hundred billion, one hundred twelve million, one hundred thousand, one hundred seventeen".