200112102100121 has 2 divisors, whose sum is σ = 200112102100122. Its totient is φ = 200112102100120.

The previous prime is 200112102100087. The next prime is 200112102100123. The reversal of 200112102100121 is 121001201211002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 170666502195721 + 29445599904400 = 13063939^2 + 5426380^2 .

It is a cyclic number.

It is not a de Polignac number, because 200112102100121 - 2²⁶ = 200112034991257 is a prime.

Together with 200112102100123, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 200112102100096 and 200112102100105.

It is not a weakly prime, because it can be changed into another prime (200112102100123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100056051050060 + 100056051050061.

It is an arithmetic number, because the mean of its divisors is an integer number (100056051050061).

Almost surely, 2^{200112102100121} is an apocalyptic number.

It is an amenable number.

200112102100121 is a deficient number, since it is larger than the sum of its proper divisors (1).

200112102100121 is an equidigital number, since it uses as much as digits as its factorization.

200112102100121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 200112102100121 its reverse (121001201211002), we get a palindrome (321113303311123).

The spelling of 200112102100121 in words is "two hundred trillion, one hundred twelve billion, one hundred two million, one hundred thousand, one hundred twenty-one".