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20011211020033 is a prime number
BaseRepresentation
bin1001000110011001110010…
…00111111101011100000001
32121212001102200222022221221
410203030321013331130001
510110330430010120113
6110321005021115041
74133522315100322
oct443147107753401
977761380868857
1020011211020033
116415785a25352
1222b23820b8a81
13b22083b535bc
144d279517c449
1524a80e20998d
hex1233391fd701

20011211020033 has 2 divisors, whose sum is σ = 20011211020034. Its totient is φ = 20011211020032.

The previous prime is 20011211020007. The next prime is 20011211020037. The reversal of 20011211020033 is 33002011211002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14370339017329 + 5640872002704 = 3790823^2 + 2375052^2 .

It is a cyclic number.

It is not a de Polignac number, because 20011211020033 - 29 = 20011211019521 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20011211019989 and 20011211020016.

It is not a weakly prime, because it can be changed into another prime (20011211020037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005605510016 + 10005605510017.

It is an arithmetic number, because the mean of its divisors is an integer number (10005605510017).

Almost surely, 220011211020033 is an apocalyptic number.

It is an amenable number.

20011211020033 is a deficient number, since it is larger than the sum of its proper divisors (1).

20011211020033 is an equidigital number, since it uses as much as digits as its factorization.

20011211020033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 20011211020033 its reverse (33002011211002), we get a palindrome (53013222231035).

The spelling of 20011211020033 in words is "twenty trillion, eleven billion, two hundred eleven million, twenty thousand, thirty-three".