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2001121122197 is a prime number
BaseRepresentation
bin11101000111101100000…
…111010001011110010101
321002022020120102202111102
4131013230013101132111
5230241244001402242
64131145150315445
7264401434612631
oct35075407213625
97068216382442
102001121122197
1170174178255a
122839b74b8b85
131169218cc1a2
146cbd7729dc1
15370c1636e32
hex1d1ec1d1795

2001121122197 has 2 divisors, whose sum is σ = 2001121122198. Its totient is φ = 2001121122196.

The previous prime is 2001121122157. The next prime is 2001121122211. The reversal of 2001121122197 is 7912211211002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1324177231441 + 676943890756 = 1150729^2 + 822766^2 .

It is a cyclic number.

It is not a de Polignac number, because 2001121122197 - 238 = 1726243215253 is a prime.

It is a super-2 number, since 2×20011211221972 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2001121122107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000560561098 + 1000560561099.

It is an arithmetic number, because the mean of its divisors is an integer number (1000560561099).

Almost surely, 22001121122197 is an apocalyptic number.

It is an amenable number.

2001121122197 is a deficient number, since it is larger than the sum of its proper divisors (1).

2001121122197 is an equidigital number, since it uses as much as digits as its factorization.

2001121122197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 29.

Adding to 2001121122197 its reverse (7912211211002), we get a palindrome (9913332333199).

The spelling of 2001121122197 in words is "two trillion, one billion, one hundred twenty-one million, one hundred twenty-two thousand, one hundred ninety-seven".