20011220113 has 2 divisors, whose sum is σ = 20011220114. Its totient is φ = 20011220112.

The previous prime is 20011220093. The next prime is 20011220153. The reversal of 20011220113 is 31102211002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19939699264 + 71520849 = 141208^2 + 8457^2 .

It is a cyclic number.

It is not a de Polignac number, because 20011220113 - 2¹⁷ = 20011089041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20011220093 and 20011220102.

It is not a weakly prime, because it can be changed into another prime (20011220153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005610056 + 10005610057.

It is an arithmetic number, because the mean of its divisors is an integer number (10005610057).

Almost surely, 2^20011220113 is an apocalyptic number.

It is an amenable number.

20011220113 is a deficient number, since it is larger than the sum of its proper divisors (1).

20011220113 is an equidigital number, since it uses as much as digits as its factorization.

20011220113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 20011220113 its reverse (31102211002), we get a palindrome (51113431115).

The spelling of 20011220113 in words is "twenty billion, eleven million, two hundred twenty thousand, one hundred thirteen".