Base | Representation |
---|---|
bin | 1011101001011110011… |
… | …1100000100001010011 |
3 | 201010112011102122111022 |
4 | 2322113213200201103 |
5 | 11234312211241201 |
6 | 231532535110055 |
7 | 20312652510563 |
oct | 2722747404123 |
9 | 633464378438 |
10 | 200112212051 |
11 | 7795a143834 |
12 | 3294921232b |
13 | 15b4164a33b |
14 | 9984d70da3 |
15 | 531323c41b |
hex | 2e979e0853 |
200112212051 has 2 divisors, whose sum is σ = 200112212052. Its totient is φ = 200112212050.
The previous prime is 200112212021. The next prime is 200112212063. The reversal of 200112212051 is 150212211002.
200112212051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200112212051 - 214 = 200112195667 is a prime.
It is not a weakly prime, because it can be changed into another prime (200112212021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100056106025 + 100056106026.
It is an arithmetic number, because the mean of its divisors is an integer number (100056106026).
Almost surely, 2200112212051 is an apocalyptic number.
200112212051 is a deficient number, since it is larger than the sum of its proper divisors (1).
200112212051 is an equidigital number, since it uses as much as digits as its factorization.
200112212051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80, while the sum is 17.
Adding to 200112212051 its reverse (150212211002), we get a palindrome (350324423053).
The spelling of 200112212051 in words is "two hundred billion, one hundred twelve million, two hundred twelve thousand, fifty-one".
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