Base | Representation |
---|---|
bin | 1011101001011110011… |
… | …1100010101110101111 |
3 | 201010112011110002220120 |
4 | 2322113213202232233 |
5 | 11234312212033403 |
6 | 231532535220023 |
7 | 20312652546144 |
oct | 2722747425657 |
9 | 633464402816 |
10 | 200112221103 |
11 | 7795a14a613 |
12 | 32949217613 |
13 | 15b416514b2 |
14 | 9984d743cb |
15 | 531323ee53 |
hex | 2e979e2baf |
200112221103 has 4 divisors (see below), whose sum is σ = 266816294808. Its totient is φ = 133408147400.
The previous prime is 200112221083. The next prime is 200112221129. The reversal of 200112221103 is 301122211002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 200112221103 - 212 = 200112217007 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200112221143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33352036848 + ... + 33352036853.
It is an arithmetic number, because the mean of its divisors is an integer number (66704073702).
Almost surely, 2200112221103 is an apocalyptic number.
200112221103 is a deficient number, since it is larger than the sum of its proper divisors (66704073705).
200112221103 is an equidigital number, since it uses as much as digits as its factorization.
200112221103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66704073704.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 200112221103 its reverse (301122211002), we get a palindrome (501234432105).
The spelling of 200112221103 in words is "two hundred billion, one hundred twelve million, two hundred twenty-one thousand, one hundred three".
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