Base | Representation |
---|---|
bin | 11101000111101100001… |
… | …011111011100110000111 |
3 | 21002022020122201210112120 |
4 | 131013230023323212013 |
5 | 230241244304441203 |
6 | 4131145232421023 |
7 | 264401451156666 |
oct | 35075413734607 |
9 | 7068218653476 |
10 | 2001122343303 |
11 | 701742436a36 |
12 | 2839b79a7773 |
13 | 116921c38c35 |
14 | 6cbd7966ddd |
15 | 370c17c8b53 |
hex | 1d1ec2fb987 |
2001122343303 has 8 divisors (see below), whose sum is σ = 2668187266416. Its totient is φ = 1334069491200.
The previous prime is 2001122343301. The next prime is 2001122343307. The reversal of 2001122343303 is 3033432211002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2001122343303 - 21 = 2001122343301 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2001122343301) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2623578 + ... + 3299303.
It is an arithmetic number, because the mean of its divisors is an integer number (333523408302).
Almost surely, 22001122343303 is an apocalyptic number.
2001122343303 is a deficient number, since it is larger than the sum of its proper divisors (667064923113).
2001122343303 is a wasteful number, since it uses less digits than its factorization.
2001122343303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6035505.
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 2001122343303 its reverse (3033432211002), we get a palindrome (5034554554305).
The spelling of 2001122343303 in words is "two trillion, one billion, one hundred twenty-two million, three hundred forty-three thousand, three hundred three".
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