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2001122343303 = 31126215922881
BaseRepresentation
bin11101000111101100001…
…011111011100110000111
321002022020122201210112120
4131013230023323212013
5230241244304441203
64131145232421023
7264401451156666
oct35075413734607
97068218653476
102001122343303
11701742436a36
122839b79a7773
13116921c38c35
146cbd7966ddd
15370c17c8b53
hex1d1ec2fb987

2001122343303 has 8 divisors (see below), whose sum is σ = 2668187266416. Its totient is φ = 1334069491200.

The previous prime is 2001122343301. The next prime is 2001122343307. The reversal of 2001122343303 is 3033432211002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2001122343303 - 21 = 2001122343301 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2001122343301) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2623578 + ... + 3299303.

It is an arithmetic number, because the mean of its divisors is an integer number (333523408302).

Almost surely, 22001122343303 is an apocalyptic number.

2001122343303 is a deficient number, since it is larger than the sum of its proper divisors (667064923113).

2001122343303 is a wasteful number, since it uses less digits than its factorization.

2001122343303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6035505.

The product of its (nonzero) digits is 2592, while the sum is 24.

Adding to 2001122343303 its reverse (3033432211002), we get a palindrome (5034554554305).

The spelling of 2001122343303 in words is "two trillion, one billion, one hundred twenty-two million, three hundred forty-three thousand, three hundred three".

Divisors: 1 3 112621 337863 5922881 17768643 667040781101 2001122343303