Base | Representation |
---|---|
bin | 10010101000110001… |
… | …000101110011011111 |
3 | 1220122121210220001212 |
4 | 102220301011303133 |
5 | 311440343412203 |
6 | 13105411455035 |
7 | 1305620221355 |
oct | 225061056337 |
9 | 56577726055 |
10 | 20011310303 |
11 | 8539954686 |
12 | 3a658b747b |
13 | 1b6bb37a1a |
14 | d7b9cb7d5 |
15 | 7c1c521d8 |
hex | 4a8c45cdf |
20011310303 has 4 divisors (see below), whose sum is σ = 20048300328. Its totient is φ = 19974320280.
The previous prime is 20011310269. The next prime is 20011310323. The reversal of 20011310303 is 30301311002.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30301311002 = 2 ⋅15150655501.
It is a cyclic number.
It is not a de Polignac number, because 20011310303 - 28 = 20011310047 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20011310323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18494201 + ... + 18495282.
It is an arithmetic number, because the mean of its divisors is an integer number (5012075082).
Almost surely, 220011310303 is an apocalyptic number.
20011310303 is a deficient number, since it is larger than the sum of its proper divisors (36990025).
20011310303 is an equidigital number, since it uses as much as digits as its factorization.
20011310303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36990024.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 20011310303 its reverse (30301311002), we get a palindrome (50312621305).
The spelling of 20011310303 in words is "twenty billion, eleven million, three hundred ten thousand, three hundred three".
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