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20011320033 = 322929128559
BaseRepresentation
bin10010101000110001…
…001000001011100001
31220122121211101102020
4102220301020023201
5311440344220113
613105412012053
71305620261625
oct225061101341
956577741366
1020011320033
118539960a21
123a65901029
131b6bb3c293
14d7b9d1185
157c1c55023
hex4a8c482e1

20011320033 has 8 divisors (see below), whose sum is σ = 26798275200. Its totient is φ = 13282622448.

The previous prime is 20011320031. The next prime is 20011320037. The reversal of 20011320033 is 33002311002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 20011320033 - 21 = 20011320031 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20011319994 and 20011320021.

It is not an unprimeable number, because it can be changed into a prime (20011320031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14563593 + ... + 14564966.

It is an arithmetic number, because the mean of its divisors is an integer number (3349784400).

Almost surely, 220011320033 is an apocalyptic number.

It is an amenable number.

20011320033 is a deficient number, since it is larger than the sum of its proper divisors (6786955167).

20011320033 is a wasteful number, since it uses less digits than its factorization.

20011320033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29128791.

The product of its (nonzero) digits is 108, while the sum is 15.

Adding to 20011320033 its reverse (33002311002), we get a palindrome (53013631035).

The spelling of 20011320033 in words is "twenty billion, eleven million, three hundred twenty thousand, thirty-three".

Divisors: 1 3 229 687 29128559 87385677 6670440011 20011320033