Base | Representation |
---|---|
bin | 10010101000110001… |
… | …001010101001000001 |
3 | 1220122121211220020120 |
4 | 102220301022221001 |
5 | 311440400030423 |
6 | 13105412130453 |
7 | 1305620333205 |
oct | 225061125101 |
9 | 56577756216 |
10 | 20011330113 |
11 | 8539968555 |
12 | 3a65906a29 |
13 | 1b6bb43a48 |
14 | d7b9d4b05 |
15 | 7c1c57ee3 |
hex | 4a8c4aa41 |
20011330113 has 32 divisors (see below), whose sum is σ = 27998487552. Its totient is φ = 12689265600.
The previous prime is 20011330103. The next prime is 20011330117. The reversal of 20011330113 is 31103311002.
It is not a de Polignac number, because 20011330113 - 29 = 20011329601 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20011330092 and 20011330101.
It is not an unprimeable number, because it can be changed into a prime (20011330117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 15499998 + ... + 15501288.
It is an arithmetic number, because the mean of its divisors is an integer number (874952736).
Almost surely, 220011330113 is an apocalyptic number.
20011330113 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
20011330113 is a deficient number, since it is larger than the sum of its proper divisors (7987157439).
20011330113 is a wasteful number, since it uses less digits than its factorization.
20011330113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2405.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 20011330113 its reverse (31103311002), we get a palindrome (51114641115).
The spelling of 20011330113 in words is "twenty billion, eleven million, three hundred thirty thousand, one hundred thirteen".
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