Base | Representation |
---|---|
bin | 11101000111101100111… |
… | …000110101010110100001 |
3 | 21002022021110212211012001 |
4 | 131013230320311112201 |
5 | 230241310313123314 |
6 | 4131150333004001 |
7 | 264401653213336 |
oct | 35075470652641 |
9 | 7068243784161 |
10 | 2001134114209 |
11 | 70174904665a |
12 | 2839bb923601 |
13 | 1169244ca879 |
14 | 6cbd934c98d |
15 | 370c2851674 |
hex | 1d1ece355a1 |
2001134114209 has 2 divisors, whose sum is σ = 2001134114210. Its totient is φ = 2001134114208.
The previous prime is 2001134114153. The next prime is 2001134114237. The reversal of 2001134114209 is 9024114311002.
It is an a-pointer prime, because the next prime (2001134114237) can be obtained adding 2001134114209 to its sum of digits (28).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1811971749025 + 189162365184 = 1346095^2 + 434928^2 .
It is a cyclic number.
It is not a de Polignac number, because 2001134114209 - 29 = 2001134113697 is a prime.
It is not a weakly prime, because it can be changed into another prime (2001134114809) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000567057104 + 1000567057105.
It is an arithmetic number, because the mean of its divisors is an integer number (1000567057105).
Almost surely, 22001134114209 is an apocalyptic number.
It is an amenable number.
2001134114209 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001134114209 is an equidigital number, since it uses as much as digits as its factorization.
2001134114209 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 28.
The spelling of 2001134114209 in words is "two trillion, one billion, one hundred thirty-four million, one hundred fourteen thousand, two hundred nine".
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