Base | Representation |
---|---|
bin | 11101000111101100111… |
… | …110001101110010110111 |
3 | 21002022021120112111111022 |
4 | 131013230332031302313 |
5 | 230241311143300142 |
6 | 4131150423131355 |
7 | 264402001210511 |
oct | 35075476156267 |
9 | 7068246474438 |
10 | 2001135525047 |
11 | 70174991a63a |
12 | 283a002a3b5b |
13 | 1169248a2a99 |
14 | 6cbd95d8bb1 |
15 | 370c2a2e6d2 |
hex | 1d1ecf8dcb7 |
2001135525047 has 2 divisors, whose sum is σ = 2001135525048. Its totient is φ = 2001135525046.
The previous prime is 2001135525019. The next prime is 2001135525139. The reversal of 2001135525047 is 7405255311002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2001135525047 - 234 = 1983955655863 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2001135524998 and 2001135525016.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2001135525007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000567762523 + 1000567762524.
It is an arithmetic number, because the mean of its divisors is an integer number (1000567762524).
Almost surely, 22001135525047 is an apocalyptic number.
2001135525047 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001135525047 is an equidigital number, since it uses as much as digits as its factorization.
2001135525047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42000, while the sum is 35.
The spelling of 2001135525047 in words is "two trillion, one billion, one hundred thirty-five million, five hundred twenty-five thousand, forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •