Base | Representation |
---|---|
bin | 101101100000001000010010… |
… | …110001010101000101001001 |
3 | 222020120021202100112020001221 |
4 | 231200020102301111011021 |
5 | 202212231300401023423 |
6 | 1545341511334242041 |
7 | 60103123452034405 |
oct | 5540102261250511 |
9 | 866507670466057 |
10 | 200120021111113 |
11 | 58845473887574 |
12 | 1a5407261b6321 |
13 | 878831095831c |
14 | 375bc09aa4105 |
15 | 18208aad14e5d |
hex | b60212c55149 |
200120021111113 has 2 divisors, whose sum is σ = 200120021111114. Its totient is φ = 200120021111112.
The previous prime is 200120021111099. The next prime is 200120021111119. The reversal of 200120021111113 is 311111120021002.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 174445663852944 + 25674357258169 = 13207788^2 + 5066987^2 .
It is a cyclic number.
It is not a de Polignac number, because 200120021111113 - 213 = 200120021102921 is a prime.
It is not a weakly prime, because it can be changed into another prime (200120021111119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100060010555556 + 100060010555557.
It is an arithmetic number, because the mean of its divisors is an integer number (100060010555557).
Almost surely, 2200120021111113 is an apocalyptic number.
It is an amenable number.
200120021111113 is a deficient number, since it is larger than the sum of its proper divisors (1).
200120021111113 is an equidigital number, since it uses as much as digits as its factorization.
200120021111113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 16.
Adding to 200120021111113 its reverse (311111120021002), we get a palindrome (511231141132115).
The spelling of 200120021111113 in words is "two hundred trillion, one hundred twenty billion, twenty-one million, one hundred eleven thousand, one hundred thirteen".
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