Base | Representation |
---|---|
bin | 11101000111110000111… |
… | …000110010011011110011 |
3 | 21002022110011010200211221 |
4 | 131013300320302123303 |
5 | 230241430002223443 |
6 | 4131201131045511 |
7 | 264403426426222 |
oct | 35076070623363 |
9 | 7068404120757 |
10 | 2001201211123 |
11 | 701782a04554 |
12 | 283a1a2a0897 |
13 | 116935390b9a |
14 | 6cc04216cb9 |
15 | 370c86a6eed |
hex | 1d1f0e326f3 |
2001201211123 has 2 divisors, whose sum is σ = 2001201211124. Its totient is φ = 2001201211122.
The previous prime is 2001201211057. The next prime is 2001201211147. The reversal of 2001201211123 is 3211121021002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2001201211123 - 217 = 2001201080051 is a prime.
It is a super-2 number, since 2×20012012111232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2001201211097 and 2001201211106.
It is not a weakly prime, because it can be changed into another prime (2001201211523) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000600605561 + 1000600605562.
It is an arithmetic number, because the mean of its divisors is an integer number (1000600605562).
Almost surely, 22001201211123 is an apocalyptic number.
2001201211123 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001201211123 is an equidigital number, since it uses as much as digits as its factorization.
2001201211123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 2001201211123 its reverse (3211121021002), we get a palindrome (5212322232125).
The spelling of 2001201211123 in words is "two trillion, one billion, two hundred one million, two hundred eleven thousand, one hundred twenty-three".
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