Search a number
-
+
20012013211 = 71281859341
BaseRepresentation
bin10010101000110011…
…110001011010011011
31220122200010121021111
4102220303301122123
5311441033410321
613105434521151
71305626206561
oct225063613233
956580117244
1020012013211
11853a2947a3
123a65b961b7
131b6c022948
14d7bb31a31
157c1d405e1
hex4a8cf169b

20012013211 has 4 divisors (see below), whose sum is σ = 20293872624. Its totient is φ = 19730153800.

The previous prime is 20012013139. The next prime is 20012013253. The reversal of 20012013211 is 11231021002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20012013211 - 27 = 20012013083 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20012013191 and 20012013200.

It is not an unprimeable number, because it can be changed into a prime (20012013011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 140929600 + ... + 140929741.

It is an arithmetic number, because the mean of its divisors is an integer number (5073468156).

Almost surely, 220012013211 is an apocalyptic number.

20012013211 is a deficient number, since it is larger than the sum of its proper divisors (281859413).

20012013211 is an equidigital number, since it uses as much as digits as its factorization.

20012013211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 281859412.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 20012013211 its reverse (11231021002), we get a palindrome (31243034213).

The spelling of 20012013211 in words is "twenty billion, twelve million, thirteen thousand, two hundred eleven".

Divisors: 1 71 281859341 20012013211