Base | Representation |
---|---|
bin | 101101100000001001010011… |
… | …000101100101110011110111 |
3 | 222020120101112112221210211101 |
4 | 231200021103011211303313 |
5 | 202212241003120224333 |
6 | 1545342210402150531 |
7 | 60103162263606241 |
oct | 5540112305456367 |
9 | 866511475853741 |
10 | 200121100164343 |
11 | 588459779951a6 |
12 | 1a540987652447 |
13 | 8788453383967 |
14 | 375bcad10d091 |
15 | 182092090e67d |
hex | b60253165cf7 |
200121100164343 has 2 divisors, whose sum is σ = 200121100164344. Its totient is φ = 200121100164342.
The previous prime is 200121100164311. The next prime is 200121100164367. The reversal of 200121100164343 is 343461001121002.
200121100164343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200121100164343 - 25 = 200121100164311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200121100174343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100060550082171 + 100060550082172.
It is an arithmetic number, because the mean of its divisors is an integer number (100060550082172).
Almost surely, 2200121100164343 is an apocalyptic number.
200121100164343 is a deficient number, since it is larger than the sum of its proper divisors (1).
200121100164343 is an equidigital number, since it uses as much as digits as its factorization.
200121100164343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 200121100164343 its reverse (343461001121002), we get a palindrome (543582101285345).
The spelling of 200121100164343 in words is "two hundred trillion, one hundred twenty-one billion, one hundred million, one hundred sixty-four thousand, three hundred forty-three".
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