200121111102113 has 2 divisors, whose sum is σ = 200121111102114. Its totient is φ = 200121111102112.

The previous prime is 200121111102109. The next prime is 200121111102119. The reversal of 200121111102113 is 311201111121002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 199697398633489 + 423712468624 = 14131433^2 + 650932^2 .

It is a cyclic number.

It is not a de Polignac number, because 200121111102113 - 2² = 200121111102109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 200121111102091 and 200121111102100.

It is not a weakly prime, because it can be changed into another prime (200121111102119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100060555551056 + 100060555551057.

It is an arithmetic number, because the mean of its divisors is an integer number (100060555551057).

Almost surely, 2^{200121111102113} is an apocalyptic number.

It is an amenable number.

200121111102113 is a deficient number, since it is larger than the sum of its proper divisors (1).

200121111102113 is an equidigital number, since it uses as much as digits as its factorization.

200121111102113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 17.

Adding to 200121111102113 its reverse (311201111121002), we get a palindrome (511322222223115).

The spelling of 200121111102113 in words is "two hundred trillion, one hundred twenty-one billion, one hundred eleven million, one hundred two thousand, one hundred thirteen".