Base | Representation |
---|---|
bin | 11101000111110001011… |
… | …110100101100110000011 |
3 | 21002022110211210010021111 |
4 | 131013301132211212003 |
5 | 230241440021320003 |
6 | 4131202123304151 |
7 | 264403606566124 |
oct | 35076136454603 |
9 | 7068424703244 |
10 | 2001211120003 |
11 | 701788562207 |
12 | 283a2167b057 |
13 | 116937450124 |
14 | 6cc0567604b |
15 | 370c94b2e6d |
hex | 1d1f17a5983 |
2001211120003 has 2 divisors, whose sum is σ = 2001211120004. Its totient is φ = 2001211120002.
The previous prime is 2001211119977. The next prime is 2001211120039. The reversal of 2001211120003 is 3000211121002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2001211120003 - 29 = 2001211119491 is a prime.
It is not a weakly prime, because it can be changed into another prime (2001211120303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000605560001 + 1000605560002.
It is an arithmetic number, because the mean of its divisors is an integer number (1000605560002).
Almost surely, 22001211120003 is an apocalyptic number.
2001211120003 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001211120003 is an equidigital number, since it uses as much as digits as its factorization.
2001211120003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 2001211120003 its reverse (3000211121002), we get a palindrome (5001422241005).
Subtracting 2001211120003 from its reverse (3000211121002), we obtain a palindrome (999000000999).
The spelling of 2001211120003 in words is "two trillion, one billion, two hundred eleven million, one hundred twenty thousand, three".
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