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2001212012113 = 31338471661983
BaseRepresentation
bin11101000111110001100…
…001111111011001010001
321002022110220110110000121
4131013301201333121101
5230241440233341423
64131202154350241
7264403620303046
oct35076141773121
97068426413017
102001212012113
11701789011496
12283a21a2b381
131169376a31c2
146cc058291cd
15370c95dc45d
hex1d1f187f651

2001212012113 has 8 divisors (see below), whose sum is σ = 2008128731648. Its totient is φ = 1994298624864.

The previous prime is 2001212012089. The next prime is 2001212012159. The reversal of 2001212012113 is 3112102121002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2001212012113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2001212082113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 373120 + ... + 2035102.

It is an arithmetic number, because the mean of its divisors is an integer number (251016091456).

Almost surely, 22001212012113 is an apocalyptic number.

It is an amenable number.

2001212012113 is a deficient number, since it is larger than the sum of its proper divisors (6916719535).

2001212012113 is a wasteful number, since it uses less digits than its factorization.

2001212012113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1666143.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 2001212012113 its reverse (3112102121002), we get a palindrome (5113314133115).

The spelling of 2001212012113 in words is "two trillion, one billion, two hundred twelve million, twelve thousand, one hundred thirteen".

Divisors: 1 313 3847 1204111 1661983 520200679 6393648601 2001212012113